2153354031131 has 4 divisors (see below), whose sum is σ = 2153367072000. Its totient is φ = 2153340990264.

The previous prime is 2153354031121. The next prime is 2153354031133. The reversal of 2153354031131 is 1311304533512.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2153354031131 - 2¹⁸ = 2153353768987 is a prime.

It is a super-2 number, since 2×2153354031131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2153354031133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6269531 + ... + 6604068.

It is an arithmetic number, because the mean of its divisors is an integer number (538341768000).

Almost surely, 2^{2153354031131} is an apocalyptic number.

2153354031131 is a deficient number, since it is larger than the sum of its proper divisors (13040869).

2153354031131 is a wasteful number, since it uses less digits than its factorization.

2153354031131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13040868.

The product of its (nonzero) digits is 16200, while the sum is 32.

Adding to 2153354031131 its reverse (1311304533512), we get a palindrome (3464658564643).

The spelling of 2153354031131 in words is "two trillion, one hundred fifty-three billion, three hundred fifty-four million, thirty-one thousand, one hundred thirty-one".