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2153424413103 = 3717808137701
BaseRepresentation
bin11111010101100010000…
…110001110000110101111
321121212100211221120111120
4133111202012032012233
5240240203122204403
64325134114352023
7311402602333005
oct37254206160657
97555324846446
102153424413103
11760297a3a207
122a942158b613
131280b4406672
1476324d64a75
153b037537e53
hex1f56218e1af

2153424413103 has 4 divisors (see below), whose sum is σ = 2871232550808. Its totient is φ = 1435616275400.

The previous prime is 2153424413089. The next prime is 2153424413113. The reversal of 2153424413103 is 3013144243512.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2153424413103 - 24 = 2153424413087 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2153424413113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 358904068848 + ... + 358904068853.

It is an arithmetic number, because the mean of its divisors is an integer number (717808137702).

Almost surely, 22153424413103 is an apocalyptic number.

2153424413103 is a deficient number, since it is larger than the sum of its proper divisors (717808137705).

2153424413103 is an equidigital number, since it uses as much as digits as its factorization.

2153424413103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 717808137704.

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 2153424413103 its reverse (3013144243512), we get a palindrome (5166568656615).

The spelling of 2153424413103 in words is "two trillion, one hundred fifty-three billion, four hundred twenty-four million, four hundred thirteen thousand, one hundred three".

Divisors: 1 3 717808137701 2153424413103