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21535013101 = 73076430443
BaseRepresentation
bin10100000011100101…
…100011100011101101
32001120210221000100211
4110003211203203231
5323100430404401
613520522022421
71361441406520
oct240345434355
961523830324
1021535013101
119150a54098
124210047a11
132052708904
141084100bb7
158608ce951
hex5039638ed

21535013101 has 4 divisors (see below), whose sum is σ = 24611443552. Its totient is φ = 18458582652.

The previous prime is 21535013099. The next prime is 21535013197. The reversal of 21535013101 is 10131053512.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21535013101 - 21 = 21535013099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21535019101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1538215215 + ... + 1538215228.

It is an arithmetic number, because the mean of its divisors is an integer number (6152860888).

Almost surely, 221535013101 is an apocalyptic number.

It is an amenable number.

21535013101 is a deficient number, since it is larger than the sum of its proper divisors (3076430451).

21535013101 is an equidigital number, since it uses as much as digits as its factorization.

21535013101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3076430450.

The product of its (nonzero) digits is 450, while the sum is 22.

Adding to 21535013101 its reverse (10131053512), we get a palindrome (31666066613).

The spelling of 21535013101 in words is "twenty-one billion, five hundred thirty-five million, thirteen thousand, one hundred one".

Divisors: 1 7 3076430443 21535013101