Base | Representation |
---|---|
bin | 1001110010110000101100… |
… | …10011000111001100111111 |
3 | 2211020202110212210022112001 |
4 | 10321120112103013030333 |
5 | 10310313334033144020 |
6 | 113445110525323131 |
7 | 4351606542555505 |
oct | 471302623071477 |
9 | 84222425708461 |
10 | 21535340131135 |
11 | 69530a5095a76 |
12 | 24b9839a064a7 |
13 | c02a0a23022c |
14 | 54645d252675 |
15 | 2752b4a9a50a |
hex | 1396164c733f |
21535340131135 has 8 divisors (see below), whose sum is σ = 25899963634800. Its totient is φ = 17189901786624.
The previous prime is 21535340131121. The next prime is 21535340131169. The reversal of 21535340131135 is 53113104353512.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 21535340131135 - 217 = 21535340000063 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21535340131094 and 21535340131103.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4796287317 + ... + 4796291806.
It is an arithmetic number, because the mean of its divisors is an integer number (3237495454350).
Almost surely, 221535340131135 is an apocalyptic number.
21535340131135 is a deficient number, since it is larger than the sum of its proper divisors (4364623503665).
21535340131135 is an equidigital number, since it uses as much as digits as its factorization.
21535340131135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9592579577.
The product of its (nonzero) digits is 81000, while the sum is 37.
Adding to 21535340131135 its reverse (53113104353512), we get a palindrome (74648444484647).
The spelling of 21535340131135 in words is "twenty-one trillion, five hundred thirty-five billion, three hundred forty million, one hundred thirty-one thousand, one hundred thirty-five".
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