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2154013151 = 6135311691
BaseRepresentation
bin1000000001100011…
…1010000111011111
312120010011012112212
42000120322013133
513402411410101
6553423551035
7104243544503
oct20030720737
95503135485
102154013151
11a0597aa64
1250145b47b
1328434cac4
1416610a303
15c91861bb
hex8063a1df

2154013151 has 4 divisors (see below), whose sum is σ = 2189324904. Its totient is φ = 2118701400.

The previous prime is 2154013129. The next prime is 2154013157. The reversal of 2154013151 is 1513104512.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2154013151 - 218 = 2153751007 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2154013157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17655785 + ... + 17655906.

It is an arithmetic number, because the mean of its divisors is an integer number (547331226).

Almost surely, 22154013151 is an apocalyptic number.

2154013151 is a deficient number, since it is larger than the sum of its proper divisors (35311753).

2154013151 is an equidigital number, since it uses as much as digits as its factorization.

2154013151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35311752.

The product of its (nonzero) digits is 600, while the sum is 23.

The square root of 2154013151 is about 46411.3472224196. The cubic root of 2154013151 is about 1291.4654241836.

Adding to 2154013151 its reverse (1513104512), we get a palindrome (3667117663).

The spelling of 2154013151 in words is "two billion, one hundred fifty-four million, thirteen thousand, one hundred fifty-one".

Divisors: 1 61 35311691 2154013151