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2154033052051 = 5147418502633
BaseRepresentation
bin11111010110000110010…
…111111111100110010011
321121220221021012122011211
4133112012113333212103
5240242424430131201
64325314335520551
7311423642562406
oct37260627774623
97556837178154
102154033052051
1176057a558701
122a9571389157
1312818053845a
1476381b19d3d
153b070bb0651
hex1f5865ff993

2154033052051 has 4 divisors (see below), whose sum is σ = 2154451559832. Its totient is φ = 2153614544272.

The previous prime is 2154033051967. The next prime is 2154033052069. The reversal of 2154033052051 is 1502503304512.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2154033052051 - 223 = 2154024663443 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2154033052091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 209246170 + ... + 209256463.

It is an arithmetic number, because the mean of its divisors is an integer number (538612889958).

Almost surely, 22154033052051 is an apocalyptic number.

2154033052051 is a deficient number, since it is larger than the sum of its proper divisors (418507781).

2154033052051 is an equidigital number, since it uses as much as digits as its factorization.

2154033052051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 418507780.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 2154033052051 its reverse (1502503304512), we get a palindrome (3656536356563).

The spelling of 2154033052051 in words is "two trillion, one hundred fifty-four billion, thirty-three million, fifty-two thousand, fifty-one".

Divisors: 1 5147 418502633 2154033052051