Base | Representation |
---|---|
bin | 11111010110001011101… |
… | …101100111011101100001 |
3 | 21121221011111201110200210 |
4 | 133112023231213131201 |
5 | 240243120341401213 |
6 | 4325331255204333 |
7 | 311426111021040 |
oct | 37261355473541 |
9 | 7557144643623 |
10 | 2154122606433 |
11 | 760616065196 |
12 | 2a95973766a9 |
13 | 128195c62605 |
14 | 7638d98c557 |
15 | 3b0789a00c3 |
hex | 1f58bb67761 |
2154122606433 has 32 divisors (see below), whose sum is σ = 3410235129600. Its totient is φ = 1183380581376.
The previous prime is 2154122606423. The next prime is 2154122606453. The reversal of 2154122606433 is 3346062214512.
It is not a de Polignac number, because 2154122606433 - 214 = 2154122590049 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 2154122606391 and 2154122606400.
It is not an unprimeable number, because it can be changed into a prime (2154122606423) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7448548 + ... + 7732341.
It is an arithmetic number, because the mean of its divisors is an integer number (106569847800).
Almost surely, 22154122606433 is an apocalyptic number.
It is an amenable number.
2154122606433 is a deficient number, since it is larger than the sum of its proper divisors (1256112523167).
2154122606433 is a wasteful number, since it uses less digits than its factorization.
2154122606433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15181161.
The product of its (nonzero) digits is 207360, while the sum is 39.
The spelling of 2154122606433 in words is "two trillion, one hundred fifty-four billion, one hundred twenty-two million, six hundred six thousand, four hundred thirty-three".
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