Base | Representation |
---|---|
bin | 1001110011001100110001… |
… | …10010001010110001110111 |
3 | 2211022012101102022222100022 |
4 | 10321212120302022301313 |
5 | 10311040222014242330 |
6 | 113500042411235355 |
7 | 4352652232256660 |
oct | 471463062126167 |
9 | 84265342288308 |
10 | 21550414212215 |
11 | 6959530006219 |
12 | 2500746148b5b |
13 | c04270216535 |
14 | 54708d23c367 |
15 | 275898144ae5 |
hex | 139998c8ac77 |
21550414212215 has 16 divisors (see below), whose sum is σ = 29554929214272. Its totient is φ = 14777389169664.
The previous prime is 21550414212179. The next prime is 21550414212227. The reversal of 21550414212215 is 51221241405512.
It is a cyclic number.
It is not a de Polignac number, because 21550414212215 - 222 = 21550410017911 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25618277 + ... + 26446113.
It is an arithmetic number, because the mean of its divisors is an integer number (1847183075892).
Almost surely, 221550414212215 is an apocalyptic number.
21550414212215 is a deficient number, since it is larger than the sum of its proper divisors (8004515002057).
21550414212215 is an equidigital number, since it uses as much as digits as its factorization.
21550414212215 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1571626.
The product of its (nonzero) digits is 32000, while the sum is 35.
Adding to 21550414212215 its reverse (51221241405512), we get a palindrome (72771655617727).
The spelling of 21550414212215 in words is "twenty-one trillion, five hundred fifty billion, four hundred fourteen million, two hundred twelve thousand, two hundred fifteen".
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