Base | Representation |
---|---|
bin | 11111010111001010001… |
… | …110011111111111110011 |
3 | 21122000212121020102012121 |
4 | 133113022032133333303 |
5 | 240302242340222003 |
6 | 4330023322535111 |
7 | 311464104522046 |
oct | 37271216377763 |
9 | 7560777212177 |
10 | 2155171414003 |
11 | 761004094903 |
12 | 2a982a667497 |
13 | 12830232b1ca |
14 | 7644cda2c5d |
15 | 3b0daac2cbd |
hex | 1f5ca39fff3 |
2155171414003 has 16 divisors (see below), whose sum is σ = 2285077513824. Its totient is φ = 2025614356480.
The previous prime is 2155171413949. The next prime is 2155171414043. The reversal of 2155171414003 is 3004141715512.
It is a cyclic number.
It is not a de Polignac number, because 2155171414003 - 29 = 2155171413491 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 2155171414003.
It is not an unprimeable number, because it can be changed into a prime (2155171414043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 73926876 + ... + 73956022.
It is an arithmetic number, because the mean of its divisors is an integer number (142817344614).
Almost surely, 22155171414003 is an apocalyptic number.
2155171414003 is a deficient number, since it is larger than the sum of its proper divisors (129906099821).
2155171414003 is a wasteful number, since it uses less digits than its factorization.
2155171414003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34982.
The product of its (nonzero) digits is 16800, while the sum is 34.
The spelling of 2155171414003 in words is "two trillion, one hundred fifty-five billion, one hundred seventy-one million, four hundred fourteen thousand, three".
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