Base | Representation |
---|---|
bin | 11111010111010010101… |
… | …011100111010111100111 |
3 | 21122001020111011010222000 |
4 | 133113102223213113213 |
5 | 240303040143422403 |
6 | 4330045351140343 |
7 | 311500446316146 |
oct | 37272253472747 |
9 | 7561214133860 |
10 | 2155313264103 |
11 | 76107716a99a |
12 | 2a986a0746b3 |
13 | 12832583568c |
14 | 76463b6975d |
15 | 3b0e82927a3 |
hex | 1f5d2ae75e7 |
2155313264103 has 16 divisors (see below), whose sum is σ = 3193290662400. Its totient is φ = 1436770220760.
The previous prime is 2155313264057. The next prime is 2155313264113. The reversal of 2155313264103 is 3014623135512.
2155313264103 is a `hidden beast` number, since 2 + 1 + 5 + 5 + 3 + 1 + 3 + 2 + 641 + 0 + 3 = 666.
It is not a de Polignac number, because 2155313264103 - 210 = 2155313263079 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2155313264113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2548513 + ... + 3287178.
It is an arithmetic number, because the mean of its divisors is an integer number (199580666400).
Almost surely, 22155313264103 is an apocalyptic number.
2155313264103 is a deficient number, since it is larger than the sum of its proper divisors (1037977398297).
2155313264103 is a wasteful number, since it uses less digits than its factorization.
2155313264103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5849379 (or 5849373 counting only the distinct ones).
The product of its (nonzero) digits is 64800, while the sum is 36.
Adding to 2155313264103 its reverse (3014623135512), we get a palindrome (5169936399615).
The spelling of 2155313264103 in words is "two trillion, one hundred fifty-five billion, three hundred thirteen million, two hundred sixty-four thousand, one hundred three".
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