Base | Representation |
---|---|
bin | 11111011000001110110… |
… | …010001100010001111001 |
3 | 21122010211202112222201221 |
4 | 133120032302030101321 |
5 | 240312121313333423 |
6 | 4330333411512041 |
7 | 311534442234412 |
oct | 37301662142171 |
9 | 7563752488657 |
10 | 2156321621113 |
11 | 7615443814a0 |
12 | 2a9aab8b8621 |
13 | 12845670a62a |
14 | 7651ba50809 |
15 | 3b156a74e5d |
hex | 1f60ec8c479 |
2156321621113 has 8 divisors (see below), whose sum is σ = 2352368769696. Its totient is φ = 1960277457600.
The previous prime is 2156321621089. The next prime is 2156321621137. The reversal of 2156321621113 is 3111261236512.
It is an interprime number because it is at equal distance from previous prime (2156321621089) and next prime (2156321621137).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-2156321621113 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2156321621413) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 927345 + ... + 2274337.
It is an arithmetic number, because the mean of its divisors is an integer number (294046096212).
Almost surely, 22156321621113 is an apocalyptic number.
It is an amenable number.
2156321621113 is a deficient number, since it is larger than the sum of its proper divisors (196047148583).
2156321621113 is a wasteful number, since it uses less digits than its factorization.
2156321621113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1492535.
The product of its digits is 12960, while the sum is 34.
Adding to 2156321621113 its reverse (3111261236512), we get a palindrome (5267582857625).
The spelling of 2156321621113 in words is "two trillion, one hundred fifty-six billion, three hundred twenty-one million, six hundred twenty-one thousand, one hundred thirteen".
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