Base | Representation |
---|---|
bin | 11111011000011100001… |
… | …011010100111101110111 |
3 | 21122011102102100120120112 |
4 | 133120130023110331313 |
5 | 240313101324022403 |
6 | 4330411555453235 |
7 | 311543141135126 |
oct | 37303413247567 |
9 | 7564372316515 |
10 | 2156546314103 |
11 | 76164a19a685 |
12 | 2a9b52bb721b |
13 | 12849112c16c |
14 | 7653d81dabd |
15 | 3b16b65a9d8 |
hex | 1f61c2d4f77 |
2156546314103 has 4 divisors (see below), whose sum is σ = 2156568254160. Its totient is φ = 2156524374048.
The previous prime is 2156546314057. The next prime is 2156546314127. The reversal of 2156546314103 is 3014136456512.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2156546314103 - 216 = 2156546248567 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2156546314903) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10821923 + ... + 11019396.
It is an arithmetic number, because the mean of its divisors is an integer number (539142063540).
Almost surely, 22156546314103 is an apocalyptic number.
2156546314103 is a deficient number, since it is larger than the sum of its proper divisors (21940057).
2156546314103 is an equidigital number, since it uses as much as digits as its factorization.
2156546314103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21940056.
The product of its (nonzero) digits is 259200, while the sum is 41.
The spelling of 2156546314103 in words is "two trillion, one hundred fifty-six billion, five hundred forty-six million, three hundred fourteen thousand, one hundred three".
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