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215665314131 = 1408115316051
BaseRepresentation
bin1100100011011010100…
…1111000100101010011
3202121200002100002121002
43020312221320211103
512013140310023011
6243024132052215
721403246631531
oct3106651704523
9677602302532
10215665314131
11835104a1603
1235969a6406b
131744c951817
14a61c811151
1559238a8c3b
hex3236a78953

215665314131 has 4 divisors (see below), whose sum is σ = 215680644264. Its totient is φ = 215649984000.

The previous prime is 215665314121. The next prime is 215665314169. The reversal of 215665314131 is 131413566512.

215665314131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 215665314131 - 234 = 198485444947 is a prime.

It is a super-2 number, since 2×2156653141312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (215665314121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7643945 + ... + 7672106.

It is an arithmetic number, because the mean of its divisors is an integer number (53920161066).

Almost surely, 2215665314131 is an apocalyptic number.

215665314131 is a deficient number, since it is larger than the sum of its proper divisors (15330133).

215665314131 is a wasteful number, since it uses less digits than its factorization.

215665314131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15330132.

The product of its digits is 64800, while the sum is 38.

The spelling of 215665314131 in words is "two hundred fifteen billion, six hundred sixty-five million, three hundred fourteen thousand, one hundred thirty-one".

Divisors: 1 14081 15316051 215665314131