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2157041153 = 13116465963
BaseRepresentation
bin1000000010010001…
…1101011000000001
312120022212001012002
42000210131120001
513404200304103
6554012513345
7104311355501
oct20044353001
95508761162
102157041153
11a07658a43
1250247b855
13284b70117
14166697a01
15c9583488
hex8091d601

2157041153 has 4 divisors (see below), whose sum is σ = 2173507248. Its totient is φ = 2140575060.

The previous prime is 2157041149. The next prime is 2157041213. The reversal of 2157041153 is 3511407512.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2157041153 - 22 = 2157041149 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2157041123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8232851 + ... + 8233112.

It is an arithmetic number, because the mean of its divisors is an integer number (543376812).

Almost surely, 22157041153 is an apocalyptic number.

It is an amenable number.

2157041153 is a deficient number, since it is larger than the sum of its proper divisors (16466095).

2157041153 is a wasteful number, since it uses less digits than its factorization.

2157041153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16466094.

The product of its (nonzero) digits is 4200, while the sum is 29.

The square root of 2157041153 is about 46443.9571203833. The cubic root of 2157041153 is about 1292.0702996139.

Adding to 2157041153 its reverse (3511407512), we get a palindrome (5668448665).

The spelling of 2157041153 in words is "two billion, one hundred fifty-seven million, forty-one thousand, one hundred fifty-three".

Divisors: 1 131 16465963 2157041153