Base | Representation |
---|---|
bin | 10100000111000111… |
… | …000101001001110111 |
3 | 2001201221011121202211 |
4 | 110013013011021313 |
5 | 323211044224421 |
6 | 13530433114251 |
7 | 1363060050205 |
oct | 240707051167 |
9 | 61657147684 |
10 | 21594133111 |
11 | 9181363901 |
12 | 42279b8987 |
13 | 2061a38175 |
14 | 108bcd0075 |
15 | 865bab9e1 |
hex | 5071c5277 |
21594133111 has 4 divisors (see below), whose sum is σ = 21628355824. Its totient is φ = 21559910400.
The previous prime is 21594133097. The next prime is 21594133243. The reversal of 21594133111 is 11133149512.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21594133111 - 25 = 21594133079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21594130111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17110410 + ... + 17111671.
It is an arithmetic number, because the mean of its divisors is an integer number (5407088956).
Almost surely, 221594133111 is an apocalyptic number.
21594133111 is a deficient number, since it is larger than the sum of its proper divisors (34222713).
21594133111 is an equidigital number, since it uses as much as digits as its factorization.
21594133111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34222712.
The product of its digits is 3240, while the sum is 31.
The spelling of 21594133111 in words is "twenty-one billion, five hundred ninety-four million, one hundred thirty-three thousand, one hundred eleven".
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