Base | Representation |
---|---|
bin | 11111110011010001000… |
… | …000110111000011001010 |
3 | 21201220202210122222002112 |
4 | 133303101000313003022 |
5 | 241301044103044434 |
6 | 4351534055502322 |
7 | 313613003635406 |
oct | 37632100670312 |
9 | 7656683588075 |
10 | 2185350049994 |
11 | 772890149791 |
12 | 2b36513879a2 |
13 | 12b10170a377 |
14 | 77ab302c106 |
15 | 3bca5235dce |
hex | 1fcd10370ca |
2185350049994 has 4 divisors (see below), whose sum is σ = 3278025074994. Its totient is φ = 1092675024996.
The previous prime is 2185350049979. The next prime is 2185350050071. The reversal of 2185350049994 is 4999400535812.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1883605278025 + 301744771969 = 1372445^2 + 549313^2 .
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 546337512497 + ... + 546337512500.
Almost surely, 22185350049994 is an apocalyptic number.
2185350049994 is a deficient number, since it is larger than the sum of its proper divisors (1092675025000).
2185350049994 is a wasteful number, since it uses less digits than its factorization.
2185350049994 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1092675024999.
The product of its (nonzero) digits is 13996800, while the sum is 59.
The spelling of 2185350049994 in words is "two trillion, one hundred eighty-five billion, three hundred fifty million, forty-nine thousand, nine hundred ninety-four".
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