Base | Representation |
---|---|
bin | 11111110011100101111… |
… | …001110111111100101111 |
3 | 21201221200020011201021112 |
4 | 133303211321313330233 |
5 | 241302303314241312 |
6 | 4352032540022235 |
7 | 313624461023642 |
oct | 37634571677457 |
9 | 7657606151245 |
10 | 2185700540207 |
11 | 772a4aa79218 |
12 | 2b372a83197b |
13 | 12b159205722 |
14 | 77b077c5a59 |
15 | 3bcc5db9d22 |
hex | 1fce5e77f2f |
2185700540207 has 4 divisors (see below), whose sum is σ = 2195329177176. Its totient is φ = 2176071903240.
The previous prime is 2185700540167. The next prime is 2185700540213. The reversal of 2185700540207 is 7020450075812.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2185700540207 - 224 = 2185683762991 is a prime.
It is a super-2 number, since 2×21857005402072 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2185700840207) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4814318144 + ... + 4814318597.
It is an arithmetic number, because the mean of its divisors is an integer number (548832294294).
Almost surely, 22185700540207 is an apocalyptic number.
2185700540207 is a deficient number, since it is larger than the sum of its proper divisors (9628636969).
2185700540207 is an equidigital number, since it uses as much as digits as its factorization.
2185700540207 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9628636968.
The product of its (nonzero) digits is 156800, while the sum is 41.
The spelling of 2185700540207 in words is "two trillion, one hundred eighty-five billion, seven hundred million, five hundred forty thousand, two hundred seven".
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