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2200112010113 = 18148724959579
BaseRepresentation
bin100000000001000000111…
…001010001001110000001
321210022212120220020110012
4200001000321101032001
5242021312133310423
64402414551514305
7314644553345123
oct40010071211601
97708776806405
102200112010113
11779075966926
122b6491088995
1312c614b40804
14786b37ab213
153c36b1ca078
hex20040e51381

2200112010113 has 8 divisors (see below), whose sum is σ = 2216810057280. Its totient is φ = 2183463883440.

The previous prime is 2200112010101. The next prime is 2200112010127. The reversal of 2200112010113 is 3110102110022.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2200112010113 - 218 = 2200111747969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2200112010193) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12391643 + ... + 12567936.

It is an arithmetic number, because the mean of its divisors is an integer number (277101257160).

Almost surely, 22200112010113 is an apocalyptic number.

It is an amenable number.

2200112010113 is a deficient number, since it is larger than the sum of its proper divisors (16698047167).

2200112010113 is a wasteful number, since it uses less digits than its factorization.

2200112010113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24960247.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 2200112010113 its reverse (3110102110022), we get a palindrome (5310214120135).

Subtracting 2200112010113 from its reverse (3110102110022), we obtain a palindrome (909990099909).

The spelling of 2200112010113 in words is "two trillion, two hundred billion, one hundred twelve million, ten thousand, one hundred thirteen".

Divisors: 1 181 487 88147 24959579 4517683799 12155314973 2200112010113