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2200201111213 = 7314314444459
BaseRepresentation
bin100000000001000110001…
…101001010011010101101
321210100002210120001011221
4200001012031022122231
5242022002441024323
64402431453343341
7314650014605110
oct40010615123255
97710083501157
102200201111213
117791111938a6
122b64b6a97b51
1312c62a439561
14786c1562577
153c373e2a55d
hex2004634a6ad

2200201111213 has 4 divisors (see below), whose sum is σ = 2514515555680. Its totient is φ = 1885886666748.

The previous prime is 2200201111187. The next prime is 2200201111261. The reversal of 2200201111213 is 3121111020022.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2200201111213 - 25 = 2200201111181 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2200201111813) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 157157222223 + ... + 157157222236.

It is an arithmetic number, because the mean of its divisors is an integer number (628628888920).

Almost surely, 22200201111213 is an apocalyptic number.

It is an amenable number.

2200201111213 is a deficient number, since it is larger than the sum of its proper divisors (314314444467).

2200201111213 is an equidigital number, since it uses as much as digits as its factorization.

2200201111213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 314314444466.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 2200201111213 its reverse (3121111020022), we get a palindrome (5321312131235).

The spelling of 2200201111213 in words is "two trillion, two hundred billion, two hundred one million, one hundred eleven thousand, two hundred thirteen".

Divisors: 1 7 314314444459 2200201111213