Base | Representation |
---|---|
bin | 10100011111100010… |
… | …110000000101010101 |
3 | 2002210111111001100020 |
4 | 110133202300011111 |
5 | 330031013240041 |
6 | 14035234535353 |
7 | 1406165153115 |
oct | 243742600525 |
9 | 62714431306 |
10 | 22004040021 |
11 | 9371785a47 |
12 | 4321137559 |
13 | 20c8937b32 |
14 | 10ca513045 |
15 | 88bb7a866 |
hex | 51f8b0155 |
22004040021 has 4 divisors (see below), whose sum is σ = 29338720032. Its totient is φ = 14669360012.
The previous prime is 22004040013. The next prime is 22004040053. The reversal of 22004040021 is 12004040022.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 22004040021 - 23 = 22004040013 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (22004000021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3667340001 + ... + 3667340006.
It is an arithmetic number, because the mean of its divisors is an integer number (7334680008).
Almost surely, 222004040021 is an apocalyptic number.
It is an amenable number.
22004040021 is a deficient number, since it is larger than the sum of its proper divisors (7334680011).
22004040021 is an equidigital number, since it uses as much as digits as its factorization.
22004040021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7334680010.
The product of its (nonzero) digits is 128, while the sum is 15.
Adding to 22004040021 its reverse (12004040022), we get a palindrome (34008080043).
Subtracting from 22004040021 its reverse (12004040022), we obtain a palindrome (9999999999).
The spelling of 22004040021 in words is "twenty-two billion, four million, forty thousand, twenty-one".
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