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22004040021 = 37334680007
BaseRepresentation
bin10100011111100010…
…110000000101010101
32002210111111001100020
4110133202300011111
5330031013240041
614035234535353
71406165153115
oct243742600525
962714431306
1022004040021
119371785a47
124321137559
1320c8937b32
1410ca513045
1588bb7a866
hex51f8b0155

22004040021 has 4 divisors (see below), whose sum is σ = 29338720032. Its totient is φ = 14669360012.

The previous prime is 22004040013. The next prime is 22004040053. The reversal of 22004040021 is 12004040022.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 22004040021 - 23 = 22004040013 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (22004000021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3667340001 + ... + 3667340006.

It is an arithmetic number, because the mean of its divisors is an integer number (7334680008).

Almost surely, 222004040021 is an apocalyptic number.

It is an amenable number.

22004040021 is a deficient number, since it is larger than the sum of its proper divisors (7334680011).

22004040021 is an equidigital number, since it uses as much as digits as its factorization.

22004040021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7334680010.

The product of its (nonzero) digits is 128, while the sum is 15.

Adding to 22004040021 its reverse (12004040022), we get a palindrome (34008080043).

Subtracting from 22004040021 its reverse (12004040022), we obtain a palindrome (9999999999).

The spelling of 22004040021 in words is "twenty-two billion, four million, forty thousand, twenty-one".

Divisors: 1 3 7334680007 22004040021