Base | Representation |
---|---|
bin | 110010000011001100100110… |
… | …010001111011000110000001 |
3 | 1001212101110101102112122201120 |
4 | 302003030212101323012001 |
5 | 212322434334321320001 |
6 | 2100054353401222453 |
7 | 64236201431626434 |
oct | 6203144621730601 |
9 | 1055343342478646 |
10 | 220122011120001 |
11 | 64157247787751 |
12 | 20831154191a29 |
13 | 95a95552c88c3 |
14 | 3c4dd6833981b |
15 | 1a6ad2a738236 |
hex | c8332647b181 |
220122011120001 has 4 divisors (see below), whose sum is σ = 293496014826672. Its totient is φ = 146748007413332.
The previous prime is 220122011119993. The next prime is 220122011120009. The reversal of 220122011120001 is 100021110221022.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (220122011119993) and next prime (220122011120009).
It is a cyclic number.
It is not a de Polignac number, because 220122011120001 - 23 = 220122011119993 is a prime.
It is a super-3 number, since 3×2201220111200013 (a number of 44 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (220122011120009) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36687001853331 + ... + 36687001853336.
It is an arithmetic number, because the mean of its divisors is an integer number (73374003706668).
Almost surely, 2220122011120001 is an apocalyptic number.
It is an amenable number.
220122011120001 is a deficient number, since it is larger than the sum of its proper divisors (73374003706671).
220122011120001 is an equidigital number, since it uses as much as digits as its factorization.
220122011120001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 73374003706670.
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 220122011120001 its reverse (100021110221022), we get a palindrome (320143121341023).
The spelling of 220122011120001 in words is "two hundred twenty trillion, one hundred twenty-two billion, eleven million, one hundred twenty thousand, one".
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