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220224344312132 = 22373914724815747
BaseRepresentation
bin110010000100101011111001…
…110100000100100101000100
31001212202020112012111102212122
4302010223321310010211010
5212331123424120442012
62100213400032505112
764246453356461366
oct6204537164044504
91055666465442778
10220224344312132
1164196690144606
1220848b533ab198
1395b60b33023b4
143c54cb51c8d36
151a6d8196ede72
hexc84af9d04944

220224344312132 has 12 divisors (see below), whose sum is σ = 385495676282640. Its totient is φ = 110082722517096.

The previous prime is 220224344312129. The next prime is 220224344312153. The reversal of 220224344312132 is 231213443422022.

It is a junction number, because it is equal to n+sod(n) for n = 220224344312092 and 220224344312101.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7362392918 + ... + 7362422829.

It is an arithmetic number, because the mean of its divisors is an integer number (32124639690220).

Almost surely, 2220224344312132 is an apocalyptic number.

It is an amenable number.

220224344312132 is a deficient number, since it is larger than the sum of its proper divisors (165271331970508).

220224344312132 is a wasteful number, since it uses less digits than its factorization.

220224344312132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14724819490 (or 14724819488 counting only the distinct ones).

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 220224344312132 its reverse (231213443422022), we get a palindrome (451437787734154).

The spelling of 220224344312132 in words is "two hundred twenty trillion, two hundred twenty-four billion, three hundred forty-four million, three hundred twelve thousand, one hundred thirty-two".

Divisors: 1 2 4 3739 7478 14956 14724815747 29449631494 58899262988 55056086078033 110112172156066 220224344312132