Base | Representation |
---|---|
bin | 100000000101110000111… |
… | …101111010010010000111 |
3 | 21210211001010020210201111 |
4 | 200011300331322102013 |
5 | 242112234124004201 |
6 | 4405021110305451 |
7 | 315215150323105 |
oct | 40056075722207 |
9 | 7724033223644 |
10 | 2205213500551 |
11 | 780253593126 |
12 | 2b7475658287 |
13 | 12cc48a153c9 |
14 | 78a3912ac75 |
15 | 3c568eccb51 |
hex | 20170f7a487 |
2205213500551 has 4 divisors (see below), whose sum is σ = 2208280557600. Its totient is φ = 2202146443504.
The previous prime is 2205213500521. The next prime is 2205213500593. The reversal of 2205213500551 is 1550053125022.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2205213500551 - 215 = 2205213467783 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2205213500521) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1533527446 + ... + 1533528883.
It is an arithmetic number, because the mean of its divisors is an integer number (552070139400).
Almost surely, 22205213500551 is an apocalyptic number.
2205213500551 is a deficient number, since it is larger than the sum of its proper divisors (3067057049).
2205213500551 is an equidigital number, since it uses as much as digits as its factorization.
2205213500551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3067057048.
The product of its (nonzero) digits is 15000, while the sum is 31.
Adding to 2205213500551 its reverse (1550053125022), we get a palindrome (3755266625573).
The spelling of 2205213500551 in words is "two trillion, two hundred five billion, two hundred thirteen million, five hundred thousand, five hundred fifty-one".
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