2211122001133 has 4 divisors (see below), whose sum is σ = 2248598645280. Its totient is φ = 2173645356988.

The previous prime is 2211122001131. The next prime is 2211122001217. The reversal of 2211122001133 is 3311002211122.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2211122001133 - 2¹ = 2211122001131 is a prime.

It is a Duffinian number.

It is a zygodrome in base 10.

It is a self number, because there is not a number n which added to its sum of digits gives 2211122001133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2211122001131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18738321985 + ... + 18738322102.

It is an arithmetic number, because the mean of its divisors is an integer number (562149661320).

Almost surely, 2^{2211122001133} is an apocalyptic number.

It is an amenable number.

2211122001133 is a deficient number, since it is larger than the sum of its proper divisors (37476644147).

2211122001133 is an equidigital number, since it uses as much as digits as its factorization.

2211122001133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37476644146.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 2211122001133 its reverse (3311002211122), we get a palindrome (5522124212255).

The spelling of 2211122001133 in words is "two trillion, two hundred eleven billion, one hundred twenty-two million, one thousand, one hundred thirty-three".