Base | Representation |
---|---|
bin | 1010000011100001011001… |
… | …01010111110001100110011 |
3 | 2220021210222102001212001111 |
4 | 11001300230222332030303 |
5 | 10344232310210232011 |
6 | 115005433002014151 |
7 | 4441325111213656 |
oct | 501605452761463 |
9 | 86253872055044 |
10 | 22111241102131 |
11 | 7055363188375 |
12 | 2591381aa7357 |
13 | c451091ca85c |
14 | 566292a7d89d |
15 | 28526ddb5121 |
hex | 141c2cabe333 |
22111241102131 has 4 divisors (see below), whose sum is σ = 22111266294712. Its totient is φ = 22111215909552.
The previous prime is 22111241102113. The next prime is 22111241102143. The reversal of 22111241102131 is 13120114211122.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 22111241102131 - 25 = 22111241102099 is a prime.
It is a super-2 number, since 2×221112411021312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (22111241132131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11230386 + ... + 13051591.
It is an arithmetic number, because the mean of its divisors is an integer number (5527816573678).
Almost surely, 222111241102131 is an apocalyptic number.
22111241102131 is a deficient number, since it is larger than the sum of its proper divisors (25192581).
22111241102131 is an equidigital number, since it uses as much as digits as its factorization.
22111241102131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25192580.
The product of its (nonzero) digits is 192, while the sum is 22.
Adding to 22111241102131 its reverse (13120114211122), we get a palindrome (35231355313253).
The spelling of 22111241102131 in words is "twenty-two trillion, one hundred eleven billion, two hundred forty-one million, one hundred two thousand, one hundred thirty-one".
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