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22111241132131 is a prime number
BaseRepresentation
bin1010000011100001011001…
…01011000101100001100011
32220021210222102010101012121
411001300230223011201203
510344232310212212011
6115005433002405111
74441325111400304
oct501605453054143
986253872111177
1022111241132131
1170553631a8968
122591381b00797
13c4510920b3c8
14566292a8a7ab
1528526ddbde71
hex141c2cac5863

22111241132131 has 2 divisors, whose sum is σ = 22111241132132. Its totient is φ = 22111241132130.

The previous prime is 22111241132089. The next prime is 22111241132171. The reversal of 22111241132131 is 13123114211122.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 22111241132131 - 219 = 22111240607843 is a prime.

It is a super-2 number, since 2×221112411321312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 22111241132096 and 22111241132105.

It is not a weakly prime, because it can be changed into another prime (22111241132171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11055620566065 + 11055620566066.

It is an arithmetic number, because the mean of its divisors is an integer number (11055620566066).

Almost surely, 222111241132131 is an apocalyptic number.

22111241132131 is a deficient number, since it is larger than the sum of its proper divisors (1).

22111241132131 is an equidigital number, since it uses as much as digits as its factorization.

22111241132131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 576, while the sum is 25.

Adding to 22111241132131 its reverse (13123114211122), we get a palindrome (35234355343253).

The spelling of 22111241132131 in words is "twenty-two trillion, one hundred eleven billion, two hundred forty-one million, one hundred thirty-two thousand, one hundred thirty-one".