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221121001113 = 3193879315809
BaseRepresentation
bin1100110111101111010…
…1101011011010011001
3210010202022011201011220
43031323311223122121
512110323434013423
6245325342242253
721655404332505
oct3157365533231
9703668151156
10221121001113
1185860049a21
1236a30b86389
1317b0c01b77c
14a9b9211305
155b428239e3
hex337bd6b699

221121001113 has 8 divisors (see below), whose sum is σ = 310345264800. Its totient is φ = 139655369088.

The previous prime is 221121001111. The next prime is 221121001163. The reversal of 221121001113 is 311100121122.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 221121001113 - 21 = 221121001111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 221121001092 and 221121001101.

It is not an unprimeable number, because it can be changed into a prime (221121001111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1939657848 + ... + 1939657961.

It is an arithmetic number, because the mean of its divisors is an integer number (38793158100).

Almost surely, 2221121001113 is an apocalyptic number.

It is an amenable number.

221121001113 is a deficient number, since it is larger than the sum of its proper divisors (89224263687).

221121001113 is a wasteful number, since it uses less digits than its factorization.

221121001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3879315831.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 221121001113 its reverse (311100121122), we get a palindrome (532221122235).

The spelling of 221121001113 in words is "two hundred twenty-one billion, one hundred twenty-one million, one thousand, one hundred thirteen".

Divisors: 1 3 19 57 3879315809 11637947427 73707000371 221121001113