Base | Representation |
---|---|
bin | 100000001011010111000… |
… | …011100000001110010011 |
3 | 21211101112210211001202222 |
4 | 200023113003200032103 |
5 | 242212040112210003 |
6 | 4411453200331255 |
7 | 315520060111031 |
oct | 40132703401623 |
9 | 7741483731688 |
10 | 2211221210003 |
11 | 7828567aa163 |
12 | 2b8671613b2b |
13 | 130695580280 |
14 | 79048d85551 |
15 | 3c7bb639c38 |
hex | 202d70e0393 |
2211221210003 has 4 divisors (see below), whose sum is σ = 2381315149248. Its totient is φ = 2041127270760.
The previous prime is 2211221209979. The next prime is 2211221210017. The reversal of 2211221210003 is 3000121221122.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2211221210003 - 214 = 2211221193619 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2211221216003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85046969603 + ... + 85046969628.
It is an arithmetic number, because the mean of its divisors is an integer number (595328787312).
Almost surely, 22211221210003 is an apocalyptic number.
2211221210003 is a deficient number, since it is larger than the sum of its proper divisors (170093939245).
2211221210003 is a wasteful number, since it uses less digits than its factorization.
2211221210003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 170093939244.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 2211221210003 its reverse (3000121221122), we get a palindrome (5211342431125).
The spelling of 2211221210003 in words is "two trillion, two hundred eleven billion, two hundred twenty-one million, two hundred ten thousand, three".
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