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22113311220000 = 253254711133137107
BaseRepresentation
bin1010000011100101010000…
…00011110110000100100000
32220022000022200100201220200
411001302220003312010200
510344301030133020000
6115010414231505200
74441430316013020
oct501625003660440
986260280321820
1022113311220000
117056225766590
12259185b228200
13c45379055280
1456640b98ba80
152853409c8500
hex141ca80f6120

22113311220000 has 5760 divisors, whose sum is σ = 112899374235648. Its totient is φ = 3956428800000.

The previous prime is 22113311219983. The next prime is 22113311220001. The reversal of 22113311220000 is 2211331122.

22113311220000 is a `hidden beast` number, since 2 + 211 + 331 + 122 + 0 + 0 + 0 + 0 = 666.

It is a super-2 number, since 2×221133112200002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a zygodrome in base 10.

It is not an unprimeable number, because it can be changed into a prime (22113311220001) by changing a digit.

It is a polite number, since it can be written in 959 ways as a sum of consecutive naturals, for example, 206666459947 + ... + 206666460053.

Almost surely, 222113311220000 is an apocalyptic number.

22113311220000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 22113311220000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (56449687117824).

22113311220000 is an abundant number, since it is smaller than the sum of its proper divisors (90786063015648).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

22113311220000 is a wasteful number, since it uses less digits than its factorization.

22113311220000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 242 (or 216 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 22113311220000 its reverse (2211331122), we get a palindrome (22115522551122).

22113311220000 divided by its reverse (2211331122) gives a 4-th power (10000 = 104).

It can be divided in two parts, 22113 and 311220000, that added together give a palindrome (311242113).

The spelling of 22113311220000 in words is "twenty-two trillion, one hundred thirteen billion, three hundred eleven million, two hundred twenty thousand".