2211411113 has 4 divisors (see below), whose sum is σ = 2211528528. Its totient is φ = 2211293700.

The previous prime is 2211411077. The next prime is 2211411143. The reversal of 2211411113 is 3111141122.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3111141122 = 2 ⋅1555570561.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2211411113 is a prime.

It is a super-2 number, since 2×2211411113² = 9780678221399797538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2211411091 and 2211411100.

It is not an unprimeable number, because it can be changed into a prime (2211411143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23363 + ... + 70488.

It is an arithmetic number, because the mean of its divisors is an integer number (552882132).

Almost surely, 2^2211411113 is an apocalyptic number.

It is an amenable number.

2211411113 is a deficient number, since it is larger than the sum of its proper divisors (117415).

2211411113 is an equidigital number, since it uses as much as digits as its factorization.

2211411113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 117414.

The product of its digits is 48, while the sum is 17.

The square root of 2211411113 is about 47025.6431428641. The cubic root of 2211411113 is about 1302.8362362257.

Adding to 2211411113 its reverse (3111141122), we get a palindrome (5322552235).

The spelling of 2211411113 in words is "two billion, two hundred eleven million, four hundred eleven thousand, one hundred thirteen".