Base | Representation |
---|---|
bin | 10100100110000111… |
… | …011010000101010011 |
3 | 2010002011222110210021 |
4 | 110212013122011103 |
5 | 330242231000111 |
6 | 14054214244311 |
7 | 1412004361243 |
oct | 244607320523 |
9 | 63064873707 |
10 | 22114312531 |
11 | 9418a53353 |
12 | 4352056697 |
13 | 211573723c |
14 | 10db019b23 |
15 | 8966add71 |
hex | 5261da153 |
22114312531 has 8 divisors (see below), whose sum is σ = 22252320000. Its totient is φ = 21976536960.
The previous prime is 22114312523. The next prime is 22114312537. The reversal of 22114312531 is 13521341122.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 22114312531 - 23 = 22114312523 is a prime.
It is a super-2 number, since 2×221143125312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 22114312496 and 22114312505.
It is not an unprimeable number, because it can be changed into a prime (22114312537) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 135345 + ... + 250093.
It is an arithmetic number, because the mean of its divisors is an integer number (2781540000).
Almost surely, 222114312531 is an apocalyptic number.
22114312531 is a deficient number, since it is larger than the sum of its proper divisors (138007469).
22114312531 is a wasteful number, since it uses less digits than its factorization.
22114312531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 115949.
The product of its digits is 1440, while the sum is 25.
Adding to 22114312531 its reverse (13521341122), we get a palindrome (35635653653).
The spelling of 22114312531 in words is "twenty-two billion, one hundred fourteen million, three hundred twelve thousand, five hundred thirty-one".
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