Base | Representation |
---|---|
bin | 100000001100010001011… |
… | …001010101100101010001 |
3 | 21211111002000121100211222 |
4 | 200030101121111211101 |
5 | 242221041200341423 |
6 | 4412134243414425 |
7 | 315553243563350 |
oct | 40142131254521 |
9 | 7744060540758 |
10 | 2212200012113 |
11 | 783209264723 |
12 | 2b88a5384415 |
13 | 1307c02a7a10 |
14 | 790dcd75997 |
15 | 3c8275303c8 |
hex | 20311655951 |
2212200012113 has 8 divisors (see below), whose sum is σ = 2722707707328. Its totient is φ = 1750312097424.
The previous prime is 2212200012107. The next prime is 2212200012133. The reversal of 2212200012113 is 3112100022122.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2212200012113 - 230 = 2211126270289 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2212200012091 and 2212200012100.
It is not an unprimeable number, because it can be changed into a prime (2212200012133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12154945031 + ... + 12154945212.
It is an arithmetic number, because the mean of its divisors is an integer number (340338463416).
Almost surely, 22212200012113 is an apocalyptic number.
It is an amenable number.
2212200012113 is a deficient number, since it is larger than the sum of its proper divisors (510507695215).
2212200012113 is a wasteful number, since it uses less digits than its factorization.
2212200012113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24309890263.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 2212200012113 its reverse (3112100022122), we get a palindrome (5324300034235).
The spelling of 2212200012113 in words is "two trillion, two hundred twelve billion, two hundred million, twelve thousand, one hundred thirteen".
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