Base | Representation |
---|---|
bin | 1100111000011101001… |
… | …0011111101000010111 |
3 | 210011020200122120100201 |
4 | 3032013102133220113 |
5 | 12111222123320112 |
6 | 245400403521331 |
7 | 21663226230433 |
oct | 3160722375027 |
9 | 704220576321 |
10 | 221313104407 |
11 | 85949528a7a |
12 | 36a85389247 |
13 | 17b3ca6c665 |
14 | a9d69399c3 |
15 | 5b5461d257 |
hex | 338749fa17 |
221313104407 has 4 divisors (see below), whose sum is σ = 221314196016. Its totient is φ = 221312012800.
The previous prime is 221313104399. The next prime is 221313104417. The reversal of 221313104407 is 704401313122.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 221313104407 - 23 = 221313104399 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (221313104417) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142219 + ... + 680332.
It is an arithmetic number, because the mean of its divisors is an integer number (55328549004).
Almost surely, 2221313104407 is an apocalyptic number.
221313104407 is a deficient number, since it is larger than the sum of its proper divisors (1091609).
221313104407 is an equidigital number, since it uses as much as digits as its factorization.
221313104407 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1091608.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 221313104407 its reverse (704401313122), we get a palindrome (925714417529).
The spelling of 221313104407 in words is "two hundred twenty-one billion, three hundred thirteen million, one hundred four thousand, four hundred seven".
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