2214403314113 has 4 divisors (see below), whose sum is σ = 2265901065648. Its totient is φ = 2162905562580.

The previous prime is 2214403314091. The next prime is 2214403314121. The reversal of 2214403314113 is 3114133044122.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2214403314113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2214403314173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25748875703 + ... + 25748875788.

It is an arithmetic number, because the mean of its divisors is an integer number (566475266412).

Almost surely, 2^{2214403314113} is an apocalyptic number.

It is an amenable number.

2214403314113 is a deficient number, since it is larger than the sum of its proper divisors (51497751535).

2214403314113 is an equidigital number, since it uses as much as digits as its factorization.

2214403314113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51497751534.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 2214403314113 its reverse (3114133044122), we get a palindrome (5328536358235).

The spelling of 2214403314113 in words is "two trillion, two hundred fourteen billion, four hundred three million, three hundred fourteen thousand, one hundred thirteen".