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2214403314173 is a prime number
BaseRepresentation
bin100000001110010100101…
…110010001000111111101
321211200202120111201001222
4200032110232101013331
5242240044222023143
64413141032043125
7315661656414461
oct40162456210775
97750676451058
102214403314173
11784139a3a116
122b91bb2334a5
13130a818c434b
147926b8324a1
153c905ba0768
hex20394b911fd

2214403314173 has 2 divisors, whose sum is σ = 2214403314174. Its totient is φ = 2214403314172.

The previous prime is 2214403314127. The next prime is 2214403314191. The reversal of 2214403314173 is 3714133044122.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2174510042884 + 39893271289 = 1474622^2 + 199733^2 .

It is a cyclic number.

It is not a de Polignac number, because 2214403314173 - 226 = 2214336205309 is a prime.

It is a super-2 number, since 2×22144033141732 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2214406314173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1107201657086 + 1107201657087.

It is an arithmetic number, because the mean of its divisors is an integer number (1107201657087).

Almost surely, 22214403314173 is an apocalyptic number.

It is an amenable number.

2214403314173 is a deficient number, since it is larger than the sum of its proper divisors (1).

2214403314173 is an equidigital number, since it uses as much as digits as its factorization.

2214403314173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48384, while the sum is 35.

Adding to 2214403314173 its reverse (3714133044122), we get a palindrome (5928536358295).

The spelling of 2214403314173 in words is "two trillion, two hundred fourteen billion, four hundred three million, three hundred fourteen thousand, one hundred seventy-three".