2221001320013 has 4 divisors (see below), whose sum is σ = 2538287222880. Its totient is φ = 1903715417148.

The previous prime is 2221001319967. The next prime is 2221001320019. The reversal of 2221001320013 is 3100231001222.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2221001320013 - 2¹⁰ = 2221001318989 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2221001319973 and 2221001320000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2221001320019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 158642951423 + ... + 158642951436.

It is an arithmetic number, because the mean of its divisors is an integer number (634571805720).

Almost surely, 2^{2221001320013} is an apocalyptic number.

It is an amenable number.

2221001320013 is a deficient number, since it is larger than the sum of its proper divisors (317285902867).

2221001320013 is an equidigital number, since it uses as much as digits as its factorization.

2221001320013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 317285902866.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 2221001320013 its reverse (3100231001222), we get a palindrome (5321232321235).

The spelling of 2221001320013 in words is "two trillion, two hundred twenty-one billion, one million, three hundred twenty thousand, thirteen".