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222213404113 = 405154853963
BaseRepresentation
bin1100111011110011110…
…0110111010111010001
3210020120102201112101021
43032330330313113101
512120043112412423
6250030004235441
722024440525061
oct3167474672721
9706512645337
10222213404113
1186270745518
123709699bb81
1317c5443c58c
14aa803333a1
155ba86a895d
hex33bcf375d1

222213404113 has 4 divisors (see below), whose sum is σ = 222268262128. Its totient is φ = 222158546100.

The previous prime is 222213404089. The next prime is 222213404129. The reversal of 222213404113 is 311404312222.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 222213404113 - 25 = 222213404081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (222213404513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27422931 + ... + 27431032.

It is an arithmetic number, because the mean of its divisors is an integer number (55567065532).

Almost surely, 2222213404113 is an apocalyptic number.

It is an amenable number.

222213404113 is a deficient number, since it is larger than the sum of its proper divisors (54858015).

222213404113 is an equidigital number, since it uses as much as digits as its factorization.

222213404113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54858014.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 222213404113 its reverse (311404312222), we get a palindrome (533617716335).

The spelling of 222213404113 in words is "two hundred twenty-two billion, two hundred thirteen million, four hundred four thousand, one hundred thirteen".

Divisors: 1 4051 54853963 222213404113