22310314011331 has 4 divisors (see below), whose sum is σ = 22310345655000. Its totient is φ = 22310282367664.

The previous prime is 22310314011319. The next prime is 22310314011347. The reversal of 22310314011331 is 13311041301322.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 22310314011331 - 2⁵ = 22310314011299 is a prime.

It is a super-3 number, since 3×22310314011331³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 22310314011296 and 22310314011305.

It is not an unprimeable number, because it can be changed into a prime (22310314011301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14739586 + ... + 16182583.

It is an arithmetic number, because the mean of its divisors is an integer number (5577586413750).

Almost surely, 2^{22310314011331} is an apocalyptic number.

22310314011331 is a deficient number, since it is larger than the sum of its proper divisors (31643669).

22310314011331 is an equidigital number, since it uses as much as digits as its factorization.

22310314011331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31643668.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 22310314011331 its reverse (13311041301322), we get a palindrome (35621355312653).

The spelling of 22310314011331 in words is "twenty-two trillion, three hundred ten billion, three hundred fourteen million, eleven thousand, three hundred thirty-one".