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22401111133 = 64334838431
BaseRepresentation
bin10100110111001101…
…011101010001011101
32010211011122100111201
4110313031131101131
5331334141024013
614142501315501
71422056205622
oct246715352135
963734570451
1022401111133
119555930395
124412105b91
13215cc9225b
141127154349
158b19613dd
hex53735d45d

22401111133 has 4 divisors (see below), whose sum is σ = 22435950208. Its totient is φ = 22366272060.

The previous prime is 22401111101. The next prime is 22401111167. The reversal of 22401111133 is 33111110422.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 22401111133 - 25 = 22401111101 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 22401111133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (22401111433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17418573 + ... + 17419858.

It is an arithmetic number, because the mean of its divisors is an integer number (5608987552).

Almost surely, 222401111133 is an apocalyptic number.

It is an amenable number.

22401111133 is a deficient number, since it is larger than the sum of its proper divisors (34839075).

22401111133 is an equidigital number, since it uses as much as digits as its factorization.

22401111133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34839074.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 22401111133 its reverse (33111110422), we get a palindrome (55512221555).

The spelling of 22401111133 in words is "twenty-two billion, four hundred one million, one hundred eleven thousand, one hundred thirty-three".

Divisors: 1 643 34838431 22401111133