2240112134113 has 4 divisors (see below), whose sum is σ = 2560128153280. Its totient is φ = 1920096114948.

The previous prime is 2240112134111. The next prime is 2240112134129. The reversal of 2240112134113 is 3114312110422.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2240112134113 - 2¹ = 2240112134111 is a prime.

It is a super-3 number, since 3×2240112134113³ (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2240112134111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160008009573 + ... + 160008009586.

It is an arithmetic number, because the mean of its divisors is an integer number (640032038320).

Almost surely, 2^{2240112134113} is an apocalyptic number.

It is an amenable number.

2240112134113 is a deficient number, since it is larger than the sum of its proper divisors (320016019167).

2240112134113 is an equidigital number, since it uses as much as digits as its factorization.

2240112134113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 320016019166.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 2240112134113 its reverse (3114312110422), we get a palindrome (5354424244535).

The spelling of 2240112134113 in words is "two trillion, two hundred forty billion, one hundred twelve million, one hundred thirty-four thousand, one hundred thirteen".