Base | Representation |
---|---|
bin | 10100110111010101… |
… | …001101100110111001 |
3 | 2010211022110122020120 |
4 | 110313111031212321 |
5 | 331340201102441 |
6 | 14143013043453 |
7 | 1422112403661 |
oct | 246725154671 |
9 | 63738418216 |
10 | 22403144121 |
11 | 9556a99846 |
12 | 4412926589 |
13 | 21605246c7 |
14 | 11275231a1 |
15 | 8b1c13966 |
hex | 53754d9b9 |
22403144121 has 4 divisors (see below), whose sum is σ = 29870858832. Its totient is φ = 14935429412.
The previous prime is 22403144087. The next prime is 22403144123. The reversal of 22403144121 is 12144130422.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 22403144121 - 27 = 22403143993 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 22403144091 and 22403144100.
It is not an unprimeable number, because it can be changed into a prime (22403144123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3733857351 + ... + 3733857356.
It is an arithmetic number, because the mean of its divisors is an integer number (7467714708).
Almost surely, 222403144121 is an apocalyptic number.
It is an amenable number.
22403144121 is a deficient number, since it is larger than the sum of its proper divisors (7467714711).
22403144121 is an equidigital number, since it uses as much as digits as its factorization.
22403144121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7467714710.
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 22403144121 its reverse (12144130422), we get a palindrome (34547274543).
The spelling of 22403144121 in words is "twenty-two billion, four hundred three million, one hundred forty-four thousand, one hundred twenty-one".
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