Base | Representation |
---|---|
bin | 1101000010101010101… |
… | …0100111001101101111 |
3 | 210102022201100020110111 |
4 | 3100222222213031233 |
5 | 12132330323110020 |
6 | 250532401120451 |
7 | 22121161352506 |
oct | 3205252471557 |
9 | 712281306414 |
10 | 224054113135 |
11 | 87025784446 |
12 | 3750b329127 |
13 | 181888b3b08 |
14 | abb69a583d |
15 | 5c650a3d5a |
hex | 342aaa736f |
224054113135 has 4 divisors (see below), whose sum is σ = 268864935768. Its totient is φ = 179243290504.
The previous prime is 224054113123. The next prime is 224054113159. The reversal of 224054113135 is 531311450422.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 224054113135 - 27 = 224054113007 is a prime.
It is a super-2 number, since 2×2240541131352 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 224054113097 and 224054113106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22405411309 + ... + 22405411318.
It is an arithmetic number, because the mean of its divisors is an integer number (67216233942).
Almost surely, 2224054113135 is an apocalyptic number.
224054113135 is a deficient number, since it is larger than the sum of its proper divisors (44810822633).
224054113135 is an equidigital number, since it uses as much as digits as its factorization.
224054113135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44810822632.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 224054113135 its reverse (531311450422), we get a palindrome (755365563557).
The spelling of 224054113135 in words is "two hundred twenty-four billion, fifty-four million, one hundred thirteen thousand, one hundred thirty-five".
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