Base | Representation |
---|---|
bin | 1010001100010011110000… |
… | …00011011010100000011011 |
3 | 2221100200021012112100012102 |
4 | 11012021320003122200123 |
5 | 10414204114244331301 |
6 | 115400243252434015 |
7 | 4502203560311603 |
oct | 506117003324033 |
9 | 87320235470172 |
10 | 22413153511451 |
11 | 716140193603a |
12 | 261b99b91890b |
13 | c677222b63c1 |
14 | 576b33b99c03 |
15 | 28d03e3d3b6b |
hex | 1462780da81b |
22413153511451 has 4 divisors (see below), whose sum is σ = 22413225402600. Its totient is φ = 22413081620304.
The previous prime is 22413153511403. The next prime is 22413153511453. The reversal of 22413153511451 is 15411535131422.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-22413153511451 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (22413153511453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35475881 + ... + 36102138.
It is an arithmetic number, because the mean of its divisors is an integer number (5603306350650).
Almost surely, 222413153511451 is an apocalyptic number.
22413153511451 is a deficient number, since it is larger than the sum of its proper divisors (71891149).
22413153511451 is an equidigital number, since it uses as much as digits as its factorization.
22413153511451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71891148.
The product of its digits is 72000, while the sum is 38.
Adding to 22413153511451 its reverse (15411535131422), we get a palindrome (37824688642873).
The spelling of 22413153511451 in words is "twenty-two trillion, four hundred thirteen billion, one hundred fifty-three million, five hundred eleven thousand, four hundred fifty-one".
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