Base | Representation |
---|---|
bin | 1010001100010100000110… |
… | …10011010111001010101011 |
3 | 2221100200202100122211002102 |
4 | 11012022003103113022223 |
5 | 10414210011103211301 |
6 | 115400314113524015 |
7 | 4502211341430050 |
oct | 506120323271253 |
9 | 87320670584072 |
10 | 22413342241451 |
11 | 7161499420747 |
12 | 261ba32b7360b |
13 | c67752425a65 |
14 | 576b50c87027 |
15 | 28d050c63b6b |
hex | 1462834d72ab |
22413342241451 has 4 divisors (see below), whose sum is σ = 25615248275952. Its totient is φ = 19211436206952.
The previous prime is 22413342241441. The next prime is 22413342241547. The reversal of 22413342241451 is 15414224331422.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-22413342241451 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (22413342241421) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1600953017240 + ... + 1600953017253.
It is an arithmetic number, because the mean of its divisors is an integer number (6403812068988).
Almost surely, 222413342241451 is an apocalyptic number.
22413342241451 is a deficient number, since it is larger than the sum of its proper divisors (3201906034501).
22413342241451 is an equidigital number, since it uses as much as digits as its factorization.
22413342241451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3201906034500.
The product of its digits is 184320, while the sum is 38.
Adding to 22413342241451 its reverse (15414224331422), we get a palindrome (37827566572873).
The spelling of 22413342241451 in words is "twenty-two trillion, four hundred thirteen billion, three hundred forty-two million, two hundred forty-one thousand, four hundred fifty-one".
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