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2242012433 = 103199910889
BaseRepresentation
bin1000010110100010…
…0110010100010001
312210020202000212112
42011220212110101
514042423344213
61010250035105
7106362535253
oct20550462421
95706660775
102242012433
11a50615141
12526a18a95
1329965119b
14173a95cd3
15d1c69ea8
hex85a26511

2242012433 has 8 divisors (see below), whose sum is σ = 2265120000. Its totient is φ = 2218930848.

The previous prime is 2242012397. The next prime is 2242012441. The reversal of 2242012433 is 3342102422.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2242012433 - 218 = 2241750289 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2242012399 and 2242012408.

It is not an unprimeable number, because it can be changed into a prime (2242012453) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 200453 + ... + 211341.

It is an arithmetic number, because the mean of its divisors is an integer number (283140000).

Almost surely, 22242012433 is an apocalyptic number.

It is an amenable number.

2242012433 is a deficient number, since it is larger than the sum of its proper divisors (23107567).

2242012433 is a wasteful number, since it uses less digits than its factorization.

2242012433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12991.

The product of its (nonzero) digits is 2304, while the sum is 23.

The square root of 2242012433 is about 47349.8936957624. The cubic root of 2242012433 is about 1308.8182402317.

Adding to 2242012433 its reverse (3342102422), we get a palindrome (5584114855).

The spelling of 2242012433 in words is "two billion, two hundred forty-two million, twelve thousand, four hundred thirty-three".

Divisors: 1 103 1999 10889 205897 1121567 21767111 2242012433