2244413034113 has 4 divisors (see below), whose sum is σ = 2245238492160. Its totient is φ = 2243587576068.

The previous prime is 2244413034041. The next prime is 2244413034139. The reversal of 2244413034113 is 3114303144422.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2244413034113 - 2¹⁴ = 2244413017729 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 2244413034113.

It is not an unprimeable number, because it can be changed into a prime (2244413034163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 412724945 + ... + 412730382.

It is an arithmetic number, because the mean of its divisors is an integer number (561309623040).

Almost surely, 2^{2244413034113} is an apocalyptic number.

It is an amenable number.

2244413034113 is a deficient number, since it is larger than the sum of its proper divisors (825458047).

2244413034113 is an equidigital number, since it uses as much as digits as its factorization.

2244413034113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 825458046.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 2244413034113 its reverse (3114303144422), we get a palindrome (5358716178535).

The spelling of 2244413034113 in words is "two trillion, two hundred forty-four billion, four hundred thirteen million, thirty-four thousand, one hundred thirteen".