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225006647133 = 375002215711
BaseRepresentation
bin1101000110001101110…
…0001111011101011101
3210111210002200222110110
43101203130033131131
512141303200202013
6251211105200233
722153605641532
oct3214334173535
9714702628413
10225006647133
1187474428324
1237736330079
13182ab0420b8
14ac672b8d89
155cbda0b2c3
hex346370f75d

225006647133 has 4 divisors (see below), whose sum is σ = 300008862848. Its totient is φ = 150004431420.

The previous prime is 225006647113. The next prime is 225006647149. The reversal of 225006647133 is 331746600522.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 225006647133 - 26 = 225006647069 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 225006647091 and 225006647100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (225006647113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37501107853 + ... + 37501107858.

It is an arithmetic number, because the mean of its divisors is an integer number (75002215712).

Almost surely, 2225006647133 is an apocalyptic number.

It is an amenable number.

225006647133 is a deficient number, since it is larger than the sum of its proper divisors (75002215715).

225006647133 is an equidigital number, since it uses as much as digits as its factorization.

225006647133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75002215714.

The product of its (nonzero) digits is 181440, while the sum is 39.

The spelling of 225006647133 in words is "two hundred twenty-five billion, six million, six hundred forty-seven thousand, one hundred thirty-three".

Divisors: 1 3 75002215711 225006647133