Base | Representation |
---|---|
bin | 100000110000111010111… |
… | …110100011100010100011 |
3 | 21222020122112221202102021 |
4 | 200300322332203202203 |
5 | 243342134344341011 |
6 | 4442203204402311 |
7 | 321445365054553 |
oct | 40607276434243 |
9 | 7866575852367 |
10 | 2251552340131 |
11 | 798972664166 |
12 | 3044483a6397 |
13 | 13442210cb03 |
14 | 7ad9350b163 |
15 | 3d87c22e471 |
hex | 20c3afa38a3 |
2251552340131 has 4 divisors (see below), whose sum is σ = 2251565980000. Its totient is φ = 2251538700264.
The previous prime is 2251552340111. The next prime is 2251552340153. The reversal of 2251552340131 is 1310432551522.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2251552340131 is a prime.
It is a super-2 number, since 2×22515523401312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2251552340101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6569256 + ... + 6903493.
It is an arithmetic number, because the mean of its divisors is an integer number (562891495000).
Almost surely, 22251552340131 is an apocalyptic number.
2251552340131 is a deficient number, since it is larger than the sum of its proper divisors (13639869).
2251552340131 is a wasteful number, since it uses less digits than its factorization.
2251552340131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13639868.
The product of its (nonzero) digits is 36000, while the sum is 34.
Adding to 2251552340131 its reverse (1310432551522), we get a palindrome (3561984891653).
The spelling of 2251552340131 in words is "two trillion, two hundred fifty-one billion, five hundred fifty-two million, three hundred forty thousand, one hundred thirty-one".
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