2253100404025 has 6 divisors (see below), whose sum is σ = 2793844501022. Its totient is φ = 1802480323200.

The previous prime is 2253100403999. The next prime is 2253100404047. The reversal of 2253100404025 is 5204040013522.

It can be written as a sum of positive squares in 3 ways, for example, as 645715102096 + 1607385301929 = 803564^2 + 1267827^2 .

It is not a de Polignac number, because 2253100404025 - 2³³ = 2244510469433 is a prime.

It is a super-3 number, since 3×2253100404025³ (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2253100403984 and 2253100404002.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 45062008056 + ... + 45062008105.

Almost surely, 2^{2253100404025} is an apocalyptic number.

2253100404025 is a gapful number since it is divisible by the number (25) formed by its first and last digit.

It is an amenable number.

2253100404025 is a deficient number, since it is larger than the sum of its proper divisors (540744096997).

2253100404025 is an equidigital number, since it uses as much as digits as its factorization.

2253100404025 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 90124016171 (or 90124016166 counting only the distinct ones).

The product of its (nonzero) digits is 9600, while the sum is 28.

Adding to 2253100404025 its reverse (5204040013522), we get a palindrome (7457140417547).

The spelling of 2253100404025 in words is "two trillion, two hundred fifty-three billion, one hundred million, four hundred four thousand, twenty-five".