Base | Representation |
---|---|
bin | 110011001110111111111111… |
… | …111000101101011001010111 |
3 | 1002112211110010010111220000221 |
4 | 303032333333320231121113 |
5 | 214013311210022244020 |
6 | 2115123412405415211 |
7 | 65314432155266554 |
oct | 6316777770553127 |
9 | 1075743103456027 |
10 | 225331162306135 |
11 | 65885455828a56 |
12 | 2133283240a507 |
13 | 9896839585072 |
14 | 3d9012d2d1a2b |
15 | 1b0b5a99c16aa |
hex | ccefffe2d657 |
225331162306135 has 4 divisors (see below), whose sum is σ = 270397394767368. Its totient is φ = 180264929844904.
The previous prime is 225331162306111. The next prime is 225331162306183. The reversal of 225331162306135 is 531603261133522.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-225331162306135 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 225331162306091 and 225331162306100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22533116230609 + ... + 22533116230618.
It is an arithmetic number, because the mean of its divisors is an integer number (67599348691842).
Almost surely, 2225331162306135 is an apocalyptic number.
225331162306135 is a deficient number, since it is larger than the sum of its proper divisors (45066232461233).
225331162306135 is an equidigital number, since it uses as much as digits as its factorization.
225331162306135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45066232461232.
The product of its (nonzero) digits is 583200, while the sum is 43.
The spelling of 225331162306135 in words is "two hundred twenty-five trillion, three hundred thirty-one billion, one hundred sixty-two million, three hundred six thousand, one hundred thirty-five".
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